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LM25010 데이터시트(PDF) 9 Page - Texas Instruments

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부품명 LM25010
상세설명  42-V, 1-A Step-Down Switching Regulator
Download  31 Pages
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제조업체  TI1 [Texas Instruments]
홈페이지  http://www.ti.com
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LM25010 데이터시트(HTML) 9 Page - Texas Instruments

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FS =
VOUT
2 x L1 x 1.4 x 1020
RL x RON
2
DC =
tON
tON + tOFF
VOUT
VIN
= tON x FS =
FS =
VOUT x (VIN ± 1.4V)
1.18 x 10
-10
x (RON + 1.4 k:) x VIN
9
LM25010, LM25010-Q1
www.ti.com
SNVS419E – DECEMBER 2005 – REVISED MAY 2016
Product Folder Links: LM25010 LM25010-Q1
Submit Documentation Feedback
Copyright © 2005–2016, Texas Instruments Incorporated
Feature Description (continued)
The LM25010 requires a minimum of 25-mV of ripple voltage at the FB pin for stable fixed-frequency operation. If
the output capacitor’s ESR is insufficient, additional series resistance may be required (R3 in the Functional
Block Diagram).
The LM25010 operates in continuous conduction mode at heavy load currents, and discontinuous conduction
mode at light load currents. In continuous conduction mode current always flows through the inductor, never
decaying to zero during the OFF-time. In this mode the operating frequency remains relatively constant with load
and line variations. The minimum load current for continuous conduction mode is one-half the inductor’s ripple
current amplitude. Calculate the operating frequency in the continuous conduction mode with Equation 2.
(2)
The buck switch duty cycle is equal to Equation 3.
(3)
Under light load conditions, the LM25010 operates in discontinuous conduction mode, with zero current flowing
through the inductor for a portion of the OFF-time. The operating frequency is always lower than that of the
continuous conduction mode, and the switching frequency varies with load current. Conversion efficiency is
maintained at a relatively high level at light loads because the switching losses diminish as the power delivered
to the load is reduced. Calculate the approximate discontinuous mode operating frequency with Equation 4.
where
RL = the load resistance
(4)
7.3.2 Start-Up Regulator (VCC)
A high voltage bias regulator is integrated within the LM25010. The input pin (VIN) can be connected directly to
line voltages between 6 V and 42 V. Referring to the Functional Block Diagram and the graph of VCC vs VIN,
when VIN is between 6 V and the bypass threshold (nominally 8.9 V), the bypass switch (Q2) is on, and VCC
tracks VIN within 100 mV to 150 mV. The bypass switch on-resistance is approximately 50 Ω, with inherent
current limiting at approximately 100 mA. When VIN is above the bypass threshold, Q2 is turned off, and VCC is
regulated at 7 V. The VCC regulator output current is limited at approximately 15 mA. When the LM25010 is
shutdown using the RON/SD pin, the VCC bypass switch is shut off, regardless of the voltage at VIN.
When VIN exceeds the bypass threshold, the time required for Q2 to shut off is approximately 2 µs to 3 µs. The
capacitor at VCC (C3) must be a minimum of 0.47 µF to prevent the voltage at VCC from rising above its
absolute maximum rating in response to a step input applied at VIN. C3 must be located as close as possible to
the LM25010 pins.
In applications with a relatively high input voltage, power dissipation in the bias regulator is a concern. An
auxiliary voltage of between 7.5 V and 14 V can be diode connected to the VCC pin (D2 in Figure 8) to shut off
the VCC regulator, reducing internal power dissipation. The current required into the VCC pin is shown in the
Typical Performance Characteristics. Internally a diode connects VCC to VIN requiring that the auxiliary voltage
be less than VIN.
The turn-on sequence is shown in Figure 1. When VCC exceeds the undervoltage lockout threshold (UVLO) of
5.25 V (t1 in Figure 1), the buck switch is enabled, and the SS pin is released to allow the softstart capacitor (C6)
to charge up. The output voltage VOUT is regulated at a reduced level which increases to the desired value as the
softstart voltage increases (t2 in Figure 1).


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